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3(x+4)=(6-2x)
We move all terms to the left:
3(x+4)-((6-2x))=0
We add all the numbers together, and all the variables
3(x+4)-((-2x+6))=0
We multiply parentheses
3x-((-2x+6))+12=0
We calculate terms in parentheses: -((-2x+6)), so:We get rid of parentheses
(-2x+6)
We get rid of parentheses
-2x+6
Back to the equation:
-(-2x+6)
3x+2x-6+12=0
We add all the numbers together, and all the variables
5x+6=0
We move all terms containing x to the left, all other terms to the right
5x=-6
x=-6/5
x=-1+1/5
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