x=3x-4(4x-8)=3(-8x-1)

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Solution for x=3x-4(4x-8)=3(-8x-1) equation: 



x=3x-4(4x-8)=3(-8x-1)

We move all terms to the left:

x-(3x-4(4x-8))=0



We calculate terms in parentheses: -(3x-4(4x-8)), so:

3x-4(4x-8)

We multiply parentheses

3x-16x+32

We add all the numbers together, and all the variables

-13x+32

Back to the equation:

-(-13x+32)



We get rid of parentheses

x+13x-32=0

We add all the numbers together, and all the variables

14x-32=0

We move all terms containing x to the left, all other terms to the right

14x=32

x=32/14

x=2+2/7

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