8(3x+1)=4(3x-2)

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Solution for 8(3x+1)=4(3x-2) equation: 



8(3x+1)=4(3x-2)

We move all terms to the left:

8(3x+1)-(4(3x-2))=0

We multiply parentheses

24x-(4(3x-2))+8=0



We calculate terms in parentheses: -(4(3x-2)), so:

4(3x-2)

We multiply parentheses

12x-8

Back to the equation:

-(12x-8)



We get rid of parentheses

24x-12x+8+8=0

We add all the numbers together, and all the variables

12x+16=0

We move all terms containing x to the left, all other terms to the right

12x=-16

x=-16/12

x=-1+1/3

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