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35x^2+25x-10=0
a = 35; b = 25; c = -10;
Δ = b2-4ac
Δ = 252-4·35·(-10)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-45}{2*35}=\frac{-70}{70} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+45}{2*35}=\frac{20}{70} =2/7 $
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