(19x+3)=(9x+16)=(6x+15)

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Solution for (19x+3)=(9x+16)=(6x+15) equation: 



(19x+3)=(9x+16)=(6x+15)

We move all terms to the left:

(19x+3)-((9x+16))=0

We get rid of parentheses

19x-((9x+16))+3=0



We calculate terms in parentheses: -((9x+16)), so:

(9x+16)

We get rid of parentheses

9x+16

Back to the equation:

-(9x+16)



We get rid of parentheses

19x-9x-16+3=0

We add all the numbers together, and all the variables

10x-13=0

We move all terms containing x to the left, all other terms to the right

10x=13

x=13/10

x=1+3/10

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