8(3c-11)-6c=8+10c

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Solution for 8(3c-11)-6c=8+10c equation: 



8(3c-11)-6c=8+10c

We move all terms to the left:

8(3c-11)-6c-(8+10c)=0

We add all the numbers together, and all the variables

8(3c-11)-6c-(10c+8)=0

We add all the numbers together, and all the variables

-6c+8(3c-11)-(10c+8)=0

We multiply parentheses

-6c+24c-(10c+8)-88=0

We get rid of parentheses

-6c+24c-10c-8-88=0

We add all the numbers together, and all the variables

8c-96=0

We move all terms containing c to the left, all other terms to the right

8c=96

c=96/8

c=12

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