-5=(-1/2)-6+b

Solution for -5=(-1/2)-6+b equation:

-5=(-1/2)-6+b

We move all terms to the left:

-5-((-1/2)-6+b)=0


Domain of the equation: 2)-6+b)!=0

b!=0/1

b!=0

b∈R


We multiply all the terms by the denominator


-((-1-5*2)-6+b)=0


We calculate terms in parentheses: -((-1-5*2)-6+b), so:

(-1-5*2)-6+b

determiningTheFunctionDomain
b-6+(-1-5*2)

We add all the numbers together, and all the variables

b-6+(-11)

We add all the numbers together, and all the variables

b-17

Back to the equation:

-(b-17)


We get rid of parentheses

-b+17=0

We add all the numbers together, and all the variables

-1b+17=0

We move all terms containing b to the left, all other terms to the right

-b=-17

b=-17/-1

b=+17