8(3b+1)=u(u+2)-4

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Solution for 8(3b+1)=u(u+2)-4 equation: 


Simplifying
8(3b + 1) = u(u + 2) + -4

Reorder the terms:
8(1 + 3b) = u(u + 2) + -4
(1 * 8 + 3b * 8) = u(u + 2) + -4
(8 + 24b) = u(u + 2) + -4

Reorder the terms:
8 + 24b = u(2 + u) + -4
8 + 24b = (2 * u + u * u) + -4
8 + 24b = (2u + u2) + -4

Reorder the terms:
8 + 24b = -4 + 2u + u2

Solving
8 + 24b = -4 + 2u + u2

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + 24b = -4 + 2u + -8 + u2

Combine like terms: 8 + -8 = 0
0 + 24b = -4 + 2u + -8 + u2
24b = -4 + 2u + -8 + u2

Reorder the terms:
24b = -4 + -8 + 2u + u2

Combine like terms: -4 + -8 = -12
24b = -12 + 2u + u2

Divide each side by '24'.
b = -0.5 + 0.08333333333u + 0.04166666667u2

Simplifying
b = -0.5 + 0.08333333333u + 0.04166666667u2

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