8(3-2y)+10y=18

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Solution for 8(3-2y)+10y=18 equation: 



8(3-2y)+10y=18

We move all terms to the left:

8(3-2y)+10y-(18)=0

We add all the numbers together, and all the variables

8(-2y+3)+10y-18=0

We add all the numbers together, and all the variables

10y+8(-2y+3)-18=0

We multiply parentheses

10y-16y+24-18=0

We add all the numbers together, and all the variables

-6y+6=0

We move all terms containing y to the left, all other terms to the right

-6y=-6

y=-6/-6

y=1

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