10(3-2y)+20y=30

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Solution for 10(3-2y)+20y=30 equation: 



10(3-2y)+20y=30

We move all terms to the left:

10(3-2y)+20y-(30)=0

We add all the numbers together, and all the variables

10(-2y+3)+20y-30=0

We add all the numbers together, and all the variables

20y+10(-2y+3)-30=0

We multiply parentheses

20y-20y+30-30=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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