8(3-2x)=-4(1+4x)+7x

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Solution for 8(3-2x)=-4(1+4x)+7x equation: 



8(3-2x)=-4(1+4x)+7x

We move all terms to the left:

8(3-2x)-(-4(1+4x)+7x)=0

We add all the numbers together, and all the variables

8(-2x+3)-(-4(4x+1)+7x)=0

We multiply parentheses

-16x-(-4(4x+1)+7x)+24=0



We calculate terms in parentheses: -(-4(4x+1)+7x), so:

-4(4x+1)+7x

We add all the numbers together, and all the variables

7x-4(4x+1)

We multiply parentheses

7x-16x-4

We add all the numbers together, and all the variables

-9x-4

Back to the equation:

-(-9x-4)



We get rid of parentheses

-16x+9x+4+24=0

We add all the numbers together, and all the variables

-7x+28=0

We move all terms containing x to the left, all other terms to the right

-7x=-28

x=-28/-7

x=+4

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