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-3c(-c-18)=-3c-18
We move all terms to the left:
-3c(-c-18)-(-3c-18)=0
We add all the numbers together, and all the variables
-3c(-1c-18)-(-3c-18)=0
We multiply parentheses
3c^2+54c-(-3c-18)=0
We get rid of parentheses
3c^2+54c+3c+18=0
We add all the numbers together, and all the variables
3c^2+57c+18=0
a = 3; b = 57; c = +18;
Δ = b2-4ac
Δ = 572-4·3·18
Δ = 3033
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3033}=\sqrt{9*337}=\sqrt{9}*\sqrt{337}=3\sqrt{337}$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(57)-3\sqrt{337}}{2*3}=\frac{-57-3\sqrt{337}}{6} $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(57)+3\sqrt{337}}{2*3}=\frac{-57+3\sqrt{337}}{6} $
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