8(2y-3)=4(y-2)

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Solution for 8(2y-3)=4(y-2) equation: 



8(2y-3)=4(y-2)

We move all terms to the left:

8(2y-3)-(4(y-2))=0

We multiply parentheses

16y-(4(y-2))-24=0



We calculate terms in parentheses: -(4(y-2)), so:

4(y-2)

We multiply parentheses

4y-8

Back to the equation:

-(4y-8)



We get rid of parentheses

16y-4y+8-24=0

We add all the numbers together, and all the variables

12y-16=0

We move all terms containing y to the left, all other terms to the right

12y=16

y=16/12

y=1+1/3

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