5(n-2)-15=4-(2n+5)

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Solution for 5(n-2)-15=4-(2n+5) equation: 



5(n-2)-15=4-(2n+5)

We move all terms to the left:

5(n-2)-15-(4-(2n+5))=0

We multiply parentheses

5n-(4-(2n+5))-10-15=0



We calculate terms in parentheses: -(4-(2n+5)), so:

4-(2n+5)

determiningTheFunctionDomain
-(2n+5)+4

We get rid of parentheses

-2n-5+4

We add all the numbers together, and all the variables

-2n-1

Back to the equation:

-(-2n-1)



We add all the numbers together, and all the variables

5n-(-2n-1)-25=0

We get rid of parentheses

5n+2n+1-25=0

We add all the numbers together, and all the variables

7n-24=0

We move all terms containing n to the left, all other terms to the right

7n=24

n=24/7

n=3+3/7

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