8(2y-1)-17(3-y)=16(3y-2)

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Solution for 8(2y-1)-17(3-y)=16(3y-2) equation: 



8(2y-1)-17(3-y)=16(3y-2)

We move all terms to the left:

8(2y-1)-17(3-y)-(16(3y-2))=0

We add all the numbers together, and all the variables

8(2y-1)-17(-1y+3)-(16(3y-2))=0

We multiply parentheses

16y+17y-(16(3y-2))-8-51=0



We calculate terms in parentheses: -(16(3y-2)), so:

16(3y-2)

We multiply parentheses

48y-32

Back to the equation:

-(48y-32)



We add all the numbers together, and all the variables

33y-(48y-32)-59=0

We get rid of parentheses

33y-48y+32-59=0

We add all the numbers together, and all the variables

-15y-27=0

We move all terms containing y to the left, all other terms to the right

-15y=27

y=27/-15

y=-1+4/5

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