8(2x+5)-9x=-3(x-4)-2

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Solution for 8(2x+5)-9x=-3(x-4)-2 equation: 



8(2x+5)-9x=-3(x-4)-2

We move all terms to the left:

8(2x+5)-9x-(-3(x-4)-2)=0

We add all the numbers together, and all the variables

-9x+8(2x+5)-(-3(x-4)-2)=0

We multiply parentheses

-9x+16x-(-3(x-4)-2)+40=0



We calculate terms in parentheses: -(-3(x-4)-2), so:

-3(x-4)-2

We multiply parentheses

-3x+12-2

We add all the numbers together, and all the variables

-3x+10

Back to the equation:

-(-3x+10)



We add all the numbers together, and all the variables

7x-(-3x+10)+40=0

We get rid of parentheses

7x+3x-10+40=0

We add all the numbers together, and all the variables

10x+30=0

We move all terms containing x to the left, all other terms to the right

10x=-30

x=-30/10

x=-3

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