8(2x+4)=6+32

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Solution for 8(2x+4)=6+32 equation: 



8(2x+4)=6+32

We move all terms to the left:

8(2x+4)-(6+32)=0

We add all the numbers together, and all the variables

8(2x+4)-38=0

We multiply parentheses

16x+32-38=0

We add all the numbers together, and all the variables

16x-6=0

We move all terms containing x to the left, all other terms to the right

16x=6

x=6/16

x=3/8

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