21(x-5)=9(3x-11)

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Solution for 21(x-5)=9(3x-11) equation: 



21(x-5)=9(3x-11)

We move all terms to the left:

21(x-5)-(9(3x-11))=0

We multiply parentheses

21x-(9(3x-11))-105=0



We calculate terms in parentheses: -(9(3x-11)), so:

9(3x-11)

We multiply parentheses

27x-99

Back to the equation:

-(27x-99)



We get rid of parentheses

21x-27x+99-105=0

We add all the numbers together, and all the variables

-6x-6=0

We move all terms containing x to the left, all other terms to the right

-6x=6

x=6/-6

x=-1

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