8(2-x)+5=7(x+1)

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Solution for 8(2-x)+5=7(x+1) equation: 



8(2-x)+5=7(x+1)

We move all terms to the left:

8(2-x)+5-(7(x+1))=0

We add all the numbers together, and all the variables

8(-1x+2)-(7(x+1))+5=0

We multiply parentheses

-8x-(7(x+1))+16+5=0



We calculate terms in parentheses: -(7(x+1)), so:

7(x+1)

We multiply parentheses

7x+7

Back to the equation:

-(7x+7)



We add all the numbers together, and all the variables

-8x-(7x+7)+21=0

We get rid of parentheses

-8x-7x-7+21=0

We add all the numbers together, and all the variables

-15x+14=0

We move all terms containing x to the left, all other terms to the right

-15x=-14

x=-14/-15

x=14/15

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