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(4x-12)/5=x-3
We move all terms to the left:
(4x-12)/5-(x-3)=0
We get rid of parentheses
(4x-12)/5-x+3=0
We multiply all the terms by the denominator
(4x-12)-x*5+3*5=0
We add all the numbers together, and all the variables
(4x-12)-x*5+15=0
Wy multiply elements
(4x-12)-5x+15=0
We get rid of parentheses
4x-5x-12+15=0
We add all the numbers together, and all the variables
-1x+3=0
We move all terms containing x to the left, all other terms to the right
-x=-3
x=-3/-1
x=+3
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