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(-2x+4)(x+7)=28
We move all terms to the left:
(-2x+4)(x+7)-(28)=0
We multiply parentheses ..
(-2x^2-14x+4x+28)-28=0
We get rid of parentheses
-2x^2-14x+4x+28-28=0
We add all the numbers together, and all the variables
-2x^2-10x=0
a = -2; b = -10; c = 0;
Δ = b2-4ac
Δ = -102-4·(-2)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10}{2*-2}=\frac{0}{-4} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10}{2*-2}=\frac{20}{-4} =-5 $
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