8(2-(x+2(x-3))+1)=3-(8-3x)

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Solution for 8(2-(x+2(x-3))+1)=3-(8-3x) equation: 



8(2-(x+2(x-3))+1)=3-(8-3x)

We move all terms to the left:

8(2-(x+2(x-3))+1)-(3-(8-3x))=0

We add all the numbers together, and all the variables

8(2-(x+2(x-3))+1)-(3-(-3x+8))=0



We calculate terms in parentheses: -(3-(-3x+8)), so:

3-(-3x+8)

determiningTheFunctionDomain
-(-3x+8)+3

We get rid of parentheses

3x-8+3

We add all the numbers together, and all the variables

3x-5

Back to the equation:

-(3x-5)



We get rid of parentheses

8(2-(x+2(x-3))+1)-3x+5=0

We add all the numbers together, and all the variables

-3x+8(2-(x+2(x-3))+1)+5=0

We move all terms containing x to the left, all other terms to the right

-3x+8(2-(x+2(x-3))+1)=-5

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