2-4(x+2)=16-(4+3x)

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Solution for 2-4(x+2)=16-(4+3x) equation: 



2-4(x+2)=16-(4+3x)

We move all terms to the left:

2-4(x+2)-(16-(4+3x))=0

We add all the numbers together, and all the variables

-4(x+2)-(16-(3x+4))+2=0

We multiply parentheses

-4x-(16-(3x+4))-8+2=0



We calculate terms in parentheses: -(16-(3x+4)), so:

16-(3x+4)

determiningTheFunctionDomain
-(3x+4)+16

We get rid of parentheses

-3x-4+16

We add all the numbers together, and all the variables

-3x+12

Back to the equation:

-(-3x+12)



We add all the numbers together, and all the variables

-4x-(-3x+12)-6=0

We get rid of parentheses

-4x+3x-12-6=0

We add all the numbers together, and all the variables

-1x-18=0

We move all terms containing x to the left, all other terms to the right

-x=18

x=18/-1

x=-18

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