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5x+15-2x=10(x+5)-35
We move all terms to the left:
5x+15-2x-(10(x+5)-35)=0
We add all the numbers together, and all the variables
3x-(10(x+5)-35)+15=0
We calculate terms in parentheses: -(10(x+5)-35), so:We get rid of parentheses
10(x+5)-35
We multiply parentheses
10x+50-35
We add all the numbers together, and all the variables
10x+15
Back to the equation:
-(10x+15)
3x-10x-15+15=0
We add all the numbers together, and all the variables
-7x=0
x=0/-7
x=0
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