8(10x2)=96

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Solution for 8(10x2)=96 equation:



8(10x^2)=96
We move all terms to the left:
8(10x^2)-(96)=0
a = 810; b = 0; c = -96;
Δ = b2-4ac
Δ = 02-4·810·(-96)
Δ = 311040
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{311040}=\sqrt{20736*15}=\sqrt{20736}*\sqrt{15}=144\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-144\sqrt{15}}{2*810}=\frac{0-144\sqrt{15}}{1620} =-\frac{144\sqrt{15}}{1620} =-\frac{4\sqrt{15}}{45} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+144\sqrt{15}}{2*810}=\frac{0+144\sqrt{15}}{1620} =\frac{144\sqrt{15}}{1620} =\frac{4\sqrt{15}}{45} $

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