48.99+.99(n-1)=1.29+1.29(n-1)

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Solution for 48.99+.99(n-1)=1.29+1.29(n-1) equation: 



48.99+.99(n-1)=1.29+1.29(n-1)

We move all terms to the left:

48.99+.99(n-1)-(1.29+1.29(n-1))=0

We multiply parentheses

0.99n-(1.29+1.29(n-1))-0.99+48.99=0



We calculate terms in parentheses: -(1.29+1.29(n-1)), so:

1.29+1.29(n-1)

determiningTheFunctionDomain
1.29(n-1)+1.29

We multiply parentheses

1.29n-1.29+1.29

We add all the numbers together, and all the variables

1.29n

Back to the equation:

-(1.29n)



We add all the numbers together, and all the variables

0.99n-(+1.29n)-0.99+48.99=0

We add all the numbers together, and all the variables

0.99n-(+1.29n)+48=0

We get rid of parentheses

0.99n-1.29n+48=0

We add all the numbers together, and all the variables

-0.3n+48=0

We move all terms containing n to the left, all other terms to the right

-0.3n=-48

n=-48/-0.3

n=+160

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