8(1-3k)=8(1+8k)-2k

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Solution for 8(1-3k)=8(1+8k)-2k equation: 



8(1-3k)=8(1+8k)-2k

We move all terms to the left:

8(1-3k)-(8(1+8k)-2k)=0

We add all the numbers together, and all the variables

8(-3k+1)-(8(8k+1)-2k)=0

We multiply parentheses

-24k-(8(8k+1)-2k)+8=0



We calculate terms in parentheses: -(8(8k+1)-2k), so:

8(8k+1)-2k

We add all the numbers together, and all the variables

-2k+8(8k+1)

We multiply parentheses

-2k+64k+8

We add all the numbers together, and all the variables

62k+8

Back to the equation:

-(62k+8)



We get rid of parentheses

-24k-62k-8+8=0

We add all the numbers together, and all the variables

-86k=0

k=0/-86

k=0

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