2(12y-28)+3y=-4

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Solution for 2(12y-28)+3y=-4 equation: 



2(12y-28)+3y=-4

We move all terms to the left:

2(12y-28)+3y-(-4)=0

We add all the numbers together, and all the variables

3y+2(12y-28)+4=0

We multiply parentheses

3y+24y-56+4=0

We add all the numbers together, and all the variables

27y-52=0

We move all terms containing y to the left, all other terms to the right

27y=52

y=52/27

y=1+25/27

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