8(1+3b)=(b-7)

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Solution for 8(1+3b)=(b-7) equation: 



8(1+3b)=(b-7)

We move all terms to the left:

8(1+3b)-((b-7))=0

We add all the numbers together, and all the variables

8(3b+1)-((b-7))=0

We multiply parentheses

24b-((b-7))+8=0



We calculate terms in parentheses: -((b-7)), so:

(b-7)

We get rid of parentheses

b-7

Back to the equation:

-(b-7)



We get rid of parentheses

24b-b+7+8=0

We add all the numbers together, and all the variables

23b+15=0

We move all terms containing b to the left, all other terms to the right

23b=-15

b=-15/23

b=-15/23

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