2(4+2b)=3/4(-8b+24)

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Solution for 2(4+2b)=3/4(-8b+24) equation: 



2(4+2b)=3/4(-8b+24)

We move all terms to the left:

2(4+2b)-(3/4(-8b+24))=0



Domain of the equation: 4(-8b+24))!=0

b∈R



We add all the numbers together, and all the variables

2(2b+4)-(3/4(-8b+24))=0

We multiply parentheses

4b-(3/4(-8b+24))+8=0

We multiply all the terms by the denominator


4b*4(-8b+24))-(3+8*4(-8b+24))=0

Wy multiply elements

16b^2(-+32b(-=0

We use the square of the difference formula

16b^2(-32b(-=0

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