8(-3x-3)=-4(7x-4)-28

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Solution for 8(-3x-3)=-4(7x-4)-28 equation: 



8(-3x-3)=-4(7x-4)-28

We move all terms to the left:

8(-3x-3)-(-4(7x-4)-28)=0

We multiply parentheses

-24x-(-4(7x-4)-28)-24=0



We calculate terms in parentheses: -(-4(7x-4)-28), so:

-4(7x-4)-28

We multiply parentheses

-28x+16-28

We add all the numbers together, and all the variables

-28x-12

Back to the equation:

-(-28x-12)



We get rid of parentheses

-24x+28x+12-24=0

We add all the numbers together, and all the variables

4x-12=0

We move all terms containing x to the left, all other terms to the right

4x=12

x=12/4

x=3

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