1x*2x=550

Solution for 1x*2x=550 equation:

1x*2x=550

We move all terms to the left:

1x*2x-(550)=0

Wy multiply elements

2x^2-550=0

a = 2; b = 0; c = -550;
Δ = b2-4ac
Δ = 02-4·2·(-550)
Δ = 4400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4400}=\sqrt{400*11}=\sqrt{400}*\sqrt{11}=20\sqrt{11}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{11}}{2*2}=\frac{0-20\sqrt{11}}{4}
=-\frac{20\sqrt{11}}{4}
=-5\sqrt{11}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{11}}{2*2}=\frac{0+20\sqrt{11}}{4}
=\frac{20\sqrt{11}}{4}
=5\sqrt{11}
$