8(-2c-2)+8=-4(2c+6)

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Solution for 8(-2c-2)+8=-4(2c+6) equation: 



8(-2c-2)+8=-4(2c+6)

We move all terms to the left:

8(-2c-2)+8-(-4(2c+6))=0

We multiply parentheses

-16c-(-4(2c+6))-16+8=0



We calculate terms in parentheses: -(-4(2c+6)), so:

-4(2c+6)

We multiply parentheses

-8c-24

Back to the equation:

-(-8c-24)



We add all the numbers together, and all the variables

-16c-(-8c-24)-8=0

We get rid of parentheses

-16c+8c+24-8=0

We add all the numbers together, and all the variables

-8c+16=0

We move all terms containing c to the left, all other terms to the right

-8c=-16

c=-16/-8

c=+2

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