53-(2c+4)=4(c+7)+7

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Solution for 53-(2c+4)=4(c+7)+7 equation: 



53-(2c+4)=4(c+7)+7

We move all terms to the left:

53-(2c+4)-(4(c+7)+7)=0

We get rid of parentheses

-2c-(4(c+7)+7)-4+53=0



We calculate terms in parentheses: -(4(c+7)+7), so:

4(c+7)+7

We multiply parentheses

4c+28+7

We add all the numbers together, and all the variables

4c+35

Back to the equation:

-(4c+35)



We add all the numbers together, and all the variables

-2c-(4c+35)+49=0

We get rid of parentheses

-2c-4c-35+49=0

We add all the numbers together, and all the variables

-6c+14=0

We move all terms containing c to the left, all other terms to the right

-6c=-14

c=-14/-6

c=2+1/3

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