X-4(x+3)=3x+12

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Solution for X-4(x+3)=3x+12 equation: 



X-4(X+3)=3X+12

We move all terms to the left:

X-4(X+3)-(3X+12)=0

We multiply parentheses

X-4X-(3X+12)-12=0

We get rid of parentheses

X-4X-3X-12-12=0

We add all the numbers together, and all the variables

-6X-24=0

We move all terms containing X to the left, all other terms to the right

-6X=24

X=24/-6

X=-4

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