8(-1+m)+3=2(m-5)1/2

Solution for 8(-1+m)+3=2(m-5)1/2 equation:

8(-1+m)+3=2(m-5)1/2

We move all terms to the left:

8(-1+m)+3-(2(m-5)1/2)=0

We add all the numbers together, and all the variables

8(m-1)-(2(m-5)1/2)+3=0

We multiply parentheses

8m-(2(m-5)1/2)-8+3=0

We multiply all the terms by the denominator


8m*2)-(2(m-5)1-8*2)+3*2)=0

We add all the numbers together, and all the variables

8m*2)-(2(m-5)1=0

Wy multiply elements

16m^2=0

a = 16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·16·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{32}=0$