2u+6=4(u-2)

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Solution for 2u+6=4(u-2) equation: 



2u+6=4(u-2)

We move all terms to the left:

2u+6-(4(u-2))=0



We calculate terms in parentheses: -(4(u-2)), so:

4(u-2)

We multiply parentheses

4u-8

Back to the equation:

-(4u-8)



We get rid of parentheses

2u-4u+8+6=0

We add all the numbers together, and all the variables

-2u+14=0

We move all terms containing u to the left, all other terms to the right

-2u=-14

u=-14/-2

u=+7

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