8(+-3)+4t=6(2t+1)-10

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Solution for 8(+-3)+4t=6(2t+1)-10 equation: 



8(+-3)+4t=6(2t+1)-10

We move all terms to the left:

8(+-3)+4t-(6(2t+1)-10)=0

We add all the numbers together, and all the variables

4t-(6(2t+1)-10)+8(-3)=0

We add all the numbers together, and all the variables

4t-(6(2t+1)-10)-24=0



We calculate terms in parentheses: -(6(2t+1)-10), so:

6(2t+1)-10

We multiply parentheses

12t+6-10

We add all the numbers together, and all the variables

12t-4

Back to the equation:

-(12t-4)



We get rid of parentheses

4t-12t+4-24=0

We add all the numbers together, and all the variables

-8t-20=0

We move all terms containing t to the left, all other terms to the right

-8t=20

t=20/-8

t=-2+1/2

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