6(x-3)/3=2(x+6)/10

Solution for 6(x-3)/3=2(x+6)/10 equation:

6(x-3)/3=2(x+6)/10

We move all terms to the left:

6(x-3)/3-(2(x+6)/10)=0

We calculate fractions


6x/()+(-(2(x+6)*3)/()=0


We calculate terms in parentheses: +(-(2(x+6)*3)/(), so:

-(2(x+6)*3)/(

We multiply all the terms by the denominator


-(2(x+6)*3)


We calculate terms in parentheses: -(2(x+6)*3), so:

2(x+6)*3

We multiply parentheses

6x+36

Back to the equation:

-(6x+36)


We get rid of parentheses

-6x-36

Back to the equation:

+(-6x-36)


We get rid of parentheses

6x/()-6x-36=0

We multiply all the terms by the denominator


6x-6x*()-36*()=0

We add all the numbers together, and all the variables

6x-6x*()=0