7z+20=4z+48

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Solution for 7z+20=4z+48 equation: 



7z+20=4z+48

We move all terms to the left:

7z+20-(4z+48)=0

We get rid of parentheses

7z-4z-48+20=0

We add all the numbers together, and all the variables

3z-28=0

We move all terms containing z to the left, all other terms to the right

3z=28

z=28/3

z=9+1/3

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