C=5/9(f-32)=25

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Solution for C=5/9(f-32)=25 equation: 



=5/9(C-32)=25

We move all terms to the left:

-(5/9(C-32))=0



Domain of the equation: 9(C-32))!=0

C∈R



We multiply all the terms by the denominator


-(5=0

We add all the numbers together, and all the variables

=0

C=0/1

C=0

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