7y-5(3y+7)=y-(7y+8)-7

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Solution for 7y-5(3y+7)=y-(7y+8)-7 equation: 



7y-5(3y+7)=y-(7y+8)-7

We move all terms to the left:

7y-5(3y+7)-(y-(7y+8)-7)=0

We multiply parentheses

7y-15y-(y-(7y+8)-7)-35=0



We calculate terms in parentheses: -(y-(7y+8)-7), so:

y-(7y+8)-7

We get rid of parentheses

y-7y-8-7

We add all the numbers together, and all the variables

-6y-15

Back to the equation:

-(-6y-15)



We add all the numbers together, and all the variables

-8y-(-6y-15)-35=0

We get rid of parentheses

-8y+6y+15-35=0

We add all the numbers together, and all the variables

-2y-20=0

We move all terms containing y to the left, all other terms to the right

-2y=20

y=20/-2

y=-10

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