(8c+9)-(2c-9)=(7c+7)+(5c-6)

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Solution for (8c+9)-(2c-9)=(7c+7)+(5c-6) equation: 



(8c+9)-(2c-9)=(7c+7)+(5c-6)

We move all terms to the left:

(8c+9)-(2c-9)-((7c+7)+(5c-6))=0

We get rid of parentheses

8c-2c-((7c+7)+(5c-6))+9+9=0



We calculate terms in parentheses: -((7c+7)+(5c-6)), so:

(7c+7)+(5c-6)

We get rid of parentheses

7c+5c+7-6

We add all the numbers together, and all the variables

12c+1

Back to the equation:

-(12c+1)



We add all the numbers together, and all the variables

6c-(12c+1)+18=0

We get rid of parentheses

6c-12c-1+18=0

We add all the numbers together, and all the variables

-6c+17=0

We move all terms containing c to the left, all other terms to the right

-6c=-17

c=-17/-6

c=2+5/6

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