7y+35=3(y+9)

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Solution for 7y+35=3(y+9) equation: 



7y+35=3(y+9)

We move all terms to the left:

7y+35-(3(y+9))=0



We calculate terms in parentheses: -(3(y+9)), so:

3(y+9)

We multiply parentheses

3y+27

Back to the equation:

-(3y+27)



We get rid of parentheses

7y-3y-27+35=0

We add all the numbers together, and all the variables

4y+8=0

We move all terms containing y to the left, all other terms to the right

4y=-8

y=-8/4

y=-2

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