(7x-4)/3=x+16

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Solution for (7x-4)/3=x+16 equation: 



(7x-4)/3=x+16

We move all terms to the left:

(7x-4)/3-(x+16)=0

We get rid of parentheses

(7x-4)/3-x-16=0

We multiply all the terms by the denominator


(7x-4)-x*3-16*3=0

We add all the numbers together, and all the variables

(7x-4)-x*3-48=0

Wy multiply elements

(7x-4)-3x-48=0

We get rid of parentheses

7x-3x-4-48=0

We add all the numbers together, and all the variables

4x-52=0

We move all terms containing x to the left, all other terms to the right

4x=52

x=52/4

x=13

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