7y+2(y-5)=5(y+1)-3

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Solution for 7y+2(y-5)=5(y+1)-3 equation:



7y+2(y-5)=5(y+1)-3
We move all terms to the left:
7y+2(y-5)-(5(y+1)-3)=0
We multiply parentheses
7y+2y-(5(y+1)-3)-10=0
We calculate terms in parentheses: -(5(y+1)-3), so:
5(y+1)-3
We multiply parentheses
5y+5-3
We add all the numbers together, and all the variables
5y+2
Back to the equation:
-(5y+2)
We add all the numbers together, and all the variables
9y-(5y+2)-10=0
We get rid of parentheses
9y-5y-2-10=0
We add all the numbers together, and all the variables
4y-12=0
We move all terms containing y to the left, all other terms to the right
4y=12
y=12/4
y=3

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