2(4x-1)=9(x+1)/12

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Solution for 2(4x-1)=9(x+1)/12 equation: 



2(4x-1)=9(x+1)/12

We move all terms to the left:

2(4x-1)-(9(x+1)/12)=0

We multiply parentheses

8x-(9(x+1)/12)-2=0

We multiply all the terms by the denominator


8x*12)-(9(x+1)-2*12)=0

We add all the numbers together, and all the variables

8x*12)-(9(x+1)=0

Wy multiply elements

96x^2=0

a = 96; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·96·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{192}=0$

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