2(7t+1)-8=t-t+5

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Solution for 2(7t+1)-8=t-t+5 equation: 



2(7t+1)-8=t-t+5

We move all terms to the left:

2(7t+1)-8-(t-t+5)=0

We add all the numbers together, and all the variables

2(7t+1)-8-5=0

We add all the numbers together, and all the variables

2(7t+1)-13=0

We multiply parentheses

14t+2-13=0

We add all the numbers together, and all the variables

14t-11=0

We move all terms containing t to the left, all other terms to the right

14t=11

t=11/14

t=11/14

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