7y+2(y-5)=(y+2)-4

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Solution for 7y+2(y-5)=(y+2)-4 equation: 



7y+2(y-5)=(y+2)-4

We move all terms to the left:

7y+2(y-5)-((y+2)-4)=0

We multiply parentheses

7y+2y-((y+2)-4)-10=0



We calculate terms in parentheses: -((y+2)-4), so:

(y+2)-4

We get rid of parentheses

y+2-4

We add all the numbers together, and all the variables

y-2

Back to the equation:

-(y-2)



We add all the numbers together, and all the variables

9y-(y-2)-10=0

We get rid of parentheses

9y-y+2-10=0

We add all the numbers together, and all the variables

8y-8=0

We move all terms containing y to the left, all other terms to the right

8y=8

y=8/8

y=1

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