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(4t+3)(3t-5)=(2t+6)(6t-7)
We move all terms to the left:
(4t+3)(3t-5)-((2t+6)(6t-7))=0
We multiply parentheses ..
(+12t^2-20t+9t-15)-((2t+6)(6t-7))=0
We calculate terms in parentheses: -((2t+6)(6t-7)), so:We get rid of parentheses
(2t+6)(6t-7)
We multiply parentheses ..
(+12t^2-14t+36t-42)
We get rid of parentheses
12t^2-14t+36t-42
We add all the numbers together, and all the variables
12t^2+22t-42
Back to the equation:
-(12t^2+22t-42)
12t^2-12t^2-20t+9t-22t-15+42=0
We add all the numbers together, and all the variables
-33t+27=0
We move all terms containing t to the left, all other terms to the right
-33t=-27
t=-27/-33
t=9/11
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